Lamabda表达式
函数式编程思想
面向对象的思想
- 做一件事情,找一个能解决这个事情的对象,调用对象的方法,完成事情
函数式编程思想
- 只要能获取结果,谁去做的,怎么做的都不重要,只重视结果,不重视过程
Lambda表达式语法
(形参列表) -> {Lambda体}
简化策略
- 当{Lambda体}中只有一句语句时,可以省略{}和{;}
- 当{Lambda体}中只有一句语句时,并且这个语句还是一个return语句,那么return也可以省略,但是如果{;}没有省略的话,return是不能省略的
- (形参列表)的类型可以省略
- 当(形参列表)的形参个数只有一个,那么可以把数据类型和()一起省略,但是形参名不能省略
- 当(形参列表)是空参时,()不能省略
函数式接口
接口中有且仅有一个抽象方法
public class TestLambda { public static void main(String[] args) { callSomething(()->System.out.println("回家吃饭")); callSomething(()->System.out.println("我爱你")); callSomething(()->System.out.println("滚蛋")); callSomething(()->System.out.println("回来")); } public static void callSomething(Call call){ call.shout(); } } interface Call { void shout(); }
StreamAPI
注意
- Stream自己不会存储元素
- Stream不会改变源对象,每次处理都会返回一个持有结果的新Stream
Stream流图示
Stream流的创建
package com.atguigu.test06;
import java.util.Arrays;
import java.util.List;
import java.util.stream.IntStream;
import java.util.stream.Stream;
import org.junit.Test;
public class Test07StreamCreate {
@Test
public void test06(){
/*
* Stream<T> iterate(T seed, UnaryOperator<T> f)
* UnaryOperator接口,SAM接口,抽象方法:
*
* UnaryOperator<T> extends Function<T,T>
* T apply(T t)
*/
Stream<Integer> stream = Stream.iterate(1, num -> num+=2);
// stream = stream.limit(10);
stream.forEach(System.out::println);
}
@Test
public void test05(){
Stream<Double> stream = Stream.generate(Math::random);
stream.forEach(System.out::println);
}
@Test
public void test04(){
Stream<Integer> stream = Stream.of(1,2,3,4,5);
stream.forEach(System.out::println);
}
@Test
public void test03(){
String[] arr = {"hello","world"};
Stream<String> stream = Arrays.stream(arr);
}
@Test
public void test02(){
int[] arr = {1,2,3,4,5};
IntStream stream = Arrays.stream(arr);
}
@Test
public void test01(){
List<Integer> list = Arrays.asList(1,2,3,4,5);
//JDK1.8中,Collection系列集合增加了方法
Stream<Integer> stream = list.stream();
}
}
Stream流的中间操作
package com.atguigu.test06;
import java.util.Arrays;
import java.util.stream.Stream;
import org.junit.Test;
public class Test08StreamMiddle {
@Test
public void test12(){
String[] arr = {"hello","world","java"};
Arrays.stream(arr)
.flatMap(t -> Stream.of(t.split("|")))//Function<T,R>接口抽象方法 R apply(T t) 现在的R是一个Stream
.forEach(System.out::println);
}
@Test
public void test11(){
String[] arr = {"hello","world","java"};
Arrays.stream(arr)
.map(t->t.toUpperCase())
.forEach(System.out::println);
}
@Test
public void test10(){
Stream.of(1,2,3,4,5)
.map(t -> t+=1)//Function<T,R>接口抽象方法 R apply(T t)
.forEach(System.out::println);
}
@Test
public void test09(){
//希望能够找出前三个最大值,前三名最大的,不重复
Stream.of(11,2,39,4,54,6,2,22,3,3,4,54,54)
.distinct()
.sorted((t1,t2) -> -Integer.compare(t1, t2))//Comparator接口 int compare(T t1, T t2)
.limit(3)
.forEach(System.out::println);
}
@Test
public void test08(){
long count = Stream.of(1,2,3,4,5,6,2,2,3,3,4,4,5)
.distinct()
.peek(System.out::println) //Consumer接口的抽象方法 void accept(T t)
.count();
System.out.println("count="+count);
}
@Test
public void test07(){
Stream.of(1,2,3,4,5,6,2,2,3,3,4,4,5)
.skip(5)
.distinct()
.filter(t -> t%3==0)
.forEach(System.out::println);
}
@Test
public void test06(){
Stream.of(1,2,3,4,5,6,2,2,3,3,4,4,5)
.skip(5)
.forEach(System.out::println);
}
@Test
public void test05(){
Stream.of(1,2,2,3,3,4,4,5,2,3,4,5,6,7)
.distinct() //(1,2,3,4,5,6,7)
.filter(t -> t%2!=0) //(1,3,5,7)
.limit(3)
.forEach(System.out::println);
}
@Test
public void test04(){
Stream.of(1,2,3,4,5,6,2,2,3,3,4,4,5)
.limit(3)
.forEach(System.out::println);
}
@Test
public void test03(){
Stream.of(1,2,3,4,5,6,2,2,3,3,4,4,5)
.distinct()
.forEach(System.out::println);
}
@Test
public void test02(){
Stream.of(1,2,3,4,5,6)
.filter(t -> t%2==0)
.forEach(System.out::println);
}
@Test
public void test01(){
//1、创建Stream
Stream<Integer> stream = Stream.of(1,2,3,4,5,6);
//2、加工处理
//过滤:filter(Predicate p)
//把里面的偶数拿出来
/*
* filter(Predicate p)
* Predicate是函数式接口,抽象方法:boolean test(T t)
*/
stream = stream.filter(t -> t%2==0);
//3、终结操作:例如:遍历
stream.forEach(System.out::println);
}
}
Stream流的终结操作
package com.atguigu.test06;
import java.util.List;
import java.util.Optional;
import java.util.stream.Collectors;
import java.util.stream.Stream;
import org.junit.Test;
public class Test09StreamEnding {
@Test
public void test14(){
List<Integer> list = Stream.of(1,2,4,5,7,8)
.filter(t -> t%2==0)
.collect(Collectors.toList());
System.out.println(list);
}
@Test
public void test13(){
Optional<Integer> max = Stream.of(1,2,4,5,7,8)
.reduce((t1,t2) -> t1>t2?t1:t2);//BinaryOperator接口 T apply(T t1, T t2)
System.out.println(max);
}
@Test
public void test12(){
Integer reduce = Stream.of(1,2,4,5,7,8)
.reduce(0, (t1,t2) -> t1+t2);//BinaryOperator接口 T apply(T t1, T t2)
System.out.println(reduce);
}
@Test
public void test11(){
Optional<Integer> max = Stream.of(1,2,4,5,7,8)
.max((t1,t2) -> Integer.compare(t1, t2));
System.out.println(max);
}
@Test
public void test10(){
Optional<Integer> opt = Stream.of(1,2,4,5,7,8)
.filter(t -> t%3==0)
.findFirst();
System.out.println(opt);
}
@Test
public void test09(){
Optional<Integer> opt = Stream.of(1,2,3,4,5,7,9)
.filter(t -> t%3==0)
.findFirst();
System.out.println(opt);
}
@Test
public void test08(){
Optional<Integer> opt = Stream.of(1,3,5,7,9).findFirst();
System.out.println(opt);
}
@Test
public void test04(){
boolean result = Stream.of(1,3,5,7,9)
.anyMatch(t -> t%2==0);
System.out.println(result);
}
@Test
public void test03(){
boolean result = Stream.of(1,3,5,7,9)
.allMatch(t -> t%2!=0);
System.out.println(result);
}
@Test
public void test02(){
long count = Stream.of(1,2,3,4,5)
.count();
System.out.println("count = " + count);
}
@Test
public void test01(){
Stream.of(1,2,3,4,5)
.forEach(System.out::println);
}
}
Stream流练习
public static void main(String[] args) {
//第一支队伍
ArrayList<String> one = new ArrayList<>();
one.add("迪丽热巴");
one.add("宋远桥");
one.add("苏星河");
one.add("石破天");
one.add("石中玉");
one.add("老子");
one.add("庄子");
one.add("洪七公");
//第二支队伍
ArrayList<String> two = new ArrayList<>();
two.add("古力娜扎");
two.add("张无忌");
two.add("赵丽颖");
two.add("张三丰");
two.add("尼古拉斯赵四");
two.add("张天爱");
two.add("张二狗");
// 第一个队伍只要名字为3个字的成员姓名;
// 第一个队伍筛选之后只要前3个人;
Stream<String> streamOne = one.stream().filter(s ‐> s.length() == 3).limit(3);
// 第二个队伍只要姓张的成员姓名;
// 第二个队伍筛选之后不要前2个人;
Stream<String> streamTwo = two.stream().filter(s ‐> s.startsWith("张")).skip(2);
// 将两个队伍合并为一个队伍;
// 根据姓名创建Person对象;
// 打印整个队伍的Person对象信息。
Stream.concat(streamOne, streamTwo).map(Person::new).forEach(System.out::println);
}