分析：

1，先查询出01号同学学习的课程

SELECT C FROM sc WHERE S='01'

 2,查询学习该相关课程的同学编号

SELECT S FROM sc WHERE C in 
(SELECT C FROM sc WHERE S='01')

 可以看到，我们分别查询了3次，所以出现多个结果，因为是or关系，所以每个选择了1、2、3课程的同学都全部取出，

3，现在需要将出现次数为3的编号取出

SELECT S FROM sc WHERE C in 
(SELECT C FROM sc WHERE S='01') 
GROUP BY S HAVING COUNT(S) =3

 看到编号为1、2、3、4的同学选了与01号同学一致的课程

4，与student表进行连表查询，取出相关信息

SELECT a.* FROM
student a LEFT JOIN sc b
ON a.S = b.S WHERE b.S in (
SELECT S FROM sc WHERE C in 
(SELECT C FROM sc WHERE S='01') 
GROUP BY S HAVING COUNT(S) =3)
GROUP BY a.S